10x2 +13x -3 = 0
ax2 bx c = 0
a = 10
b = 13
c = -3
Δ = b2-4ac
Δ = 13² - (4 * 10 * -3)
Δ = 169 - (4*-30)
Δ = 169 - (-120)
Δ = 289 Δ > 0
10x2+13x-3=0
x = -b ∓ √Δ 2a
x' = -13 - √289 2*10 = -13 - 17.0 20 = -30.0 20 = -1.5
x" = -13 + √289 2*10 = -13 + 17.0 20 = 4.0 20 = 0.2
x' = -150.0
x" = 20.0
S = {x ∈ R / x' = -150.0, x" = 20.0 }