-12x2 +22x -10 = 0
ax2 bx c = 0
a = -12
b = 22
c = -10
Δ = b2-4ac
Δ = 22² - (4 * -12 * -10)
Δ = 484 - (4*120)
Δ = 484 - (480)
Δ = 4 Δ > 0
-12x2+22x-10=0
x = -b ∓ √Δ 2a
x' = -22 - √4 2*-12 = -22 - 2.0 -24 = -24.0 -24 = 1.0
x" = -22 + √4 2*-12 = -22 + 2.0 -24 = -20.0 -24 = 0.833333333333
x' = 144.0
x" = 120.0
S = {x ∈ R / x' = 144.0, x" = 120.0 }